A block is kept on a smooth inclined plane of angle of inclination 30º that moves with a constant acceleration so that the block does not slide relative to the inclined plane. Let F 1 be the contact force between the block and the plane. Now the inclined plane stops and let F 2 be the contact force between the two in this case. Then F 1 /F 2 is:
Text Solution
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Surface is smooth. Therefore, force of friction between the block and the plane is zero. So, contact force is really the normal reaction between the two.
In the first case F 1 sin 30º = ma
and F 1 cos 30 0 = mg
or F 1 = 
and in the second case
F 2 = mg cos 30 0
= 
= 
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